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Q.

A body cools down from 60°C to 55°C in 30 s. Using Newton’s law of cooling, calculate the approximate time taken by same body to cool down from 5 5°Cto 50°C. Assume that the temperature of surroundings is 45°C.

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answer is 50.

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Detailed Solution

According to Newton’s law of coolingθ1−θ2t=Kθ1+θ22−θ060−5530=K60+552−45……………(i)Similarly, for 2nd case,55−50t=K55+502−45……………(ii)Dividing Eq. (i) by Eq. (ii), we get, t = 50

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