Questions
A body cools from 600C to 500C in 10 min. If room temperature is 250C. Temperature of body at the end
of next 10 min, will be [UP CPMT 2012]
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a
38.50C
b
400C
c
450C
d
42.850C
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Correct option is D
Newton's cooling law is given as θ1−θ2t=kθ1+θ22−θ0Given, θ0=25∘C,θ1=60∘C,t=10min and θ2=50∘C∴ 60−5010=k60+502−25We get, k=130 units and t2=10minAgain, θ2=θ,θ1=50∘C,θ0=25∘C∴ 50−θ10=13050+θ2−25⇒ θ=42.85∘CSimilar Questions
A calorimeter of mass 0.2 kg and specific heat 900 Containing 0.5 kg of a liquid of specific heat 2400J/kg/K. Its temperature falls from
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