Questions
A body cools from 80°C to 64°C in 5 min and same body cools from 80°C to 52°C in 10 min. What is the temperature of the surrounding?
detailed solution
Correct option is A
θ1-θ2t=Kθ1+θ22-θ0 80-645=K80+642-θ0⇒⇒1 and 80-5210=K80+522-θ0⇒⇒2 dividing equations 1 by 2 solving for θ θ0=240CTalk to our academic expert!
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