Questions
A body cools from to in 6 minutes. If temperature of surroundings is . What is the temperature after 12 minutes?
detailed solution
Correct option is C
initial temperature of the body is θ1=70oc after 6 minutestemperature of body is θ2=50oc; surrounding temperature is θ0=30oc; final temperature of body is θ =? time t1=6 minutestime t2=12 minutesfrom newton law of cooling dθdt=-kθ1+θ22-θ0---(1) substitute given values in eqn(1) θ1-θ2time=-kθ1+θ22-θ070-506=-k70+502-30206=-k60-30k=-19---(2) substitute second part of question, given values and eqn(2) in eqn(1)50-θ12=--1950+θ2-30 ⇒θ=340CSimilar Questions
A body cools down from 60°C to 55°C in 30 s. Using Newton’s law of cooling, calculate the approximate time taken by same body to cool down from 5 5°C
to 50°C. Assume that the temperature of surroundings is 45°C.
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