Q.

A body cools from 50oC to 49.9oC in 5 sec. It cools from 40oC to 39.9oC in t sec. Assuming Newton's law of cooling to be valid and temperature of surrounding is at 30oC, value of t25 will be ___.

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answer is 0.40.

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Detailed Solution

From θ1−θ2t=kθ1+θ22−θ0 We have 0.15=k99.92-30 and 0.1t=k79.92-30 ⇒t=10.025s ∴t25=0.40
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A body cools from 50oC to 49.9oC in 5 sec. It cools from 40oC to 39.9oC in t sec. Assuming Newton's law of cooling to be valid and temperature of surrounding is at 30oC, value of t25 will be ___.