Q.
A body cools from 50oC to 49.9oC in 5 sec. It cools from 40oC to 39.9oC in t sec. Assuming Newton's law of cooling to be valid and temperature of surrounding is at 30oC, value of t25 will be ___.
see full answer
Start JEE / NEET / Foundation preparation at rupees 99/day !!
21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya
answer is 0.40.
(Unlock A.I Detailed Solution for FREE)
Ready to Test Your Skills?
Check your Performance Today with our Free Mock Test used by Toppers!
Take Free Test
Detailed Solution
From θ1−θ2t=kθ1+θ22−θ0 We have 0.15=k99.92-30 and 0.1t=k79.92-30 ⇒t=10.025s ∴t25=0.40
Watch 3-min video & get full concept clarity