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Q.

A body cools from a temperature 3T to a temperature 2T in 10 minutes. The room temperature is T. Assume that Newton's law of cooling is applicable. The temperature of the body at the end of next 10 minutes will be

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a

43T

b

T

c

74T

d

32T

answer is D.

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Detailed Solution

Newton's law of coolingT1-T2t = k(T1+T22-T)3T-2T10 = k(5T-2T2)⇒ T10 = k(3T2)------(i)⇒ 2T-T'10 = k(2T+T'2-T)⇒ 2T-T'10 = k(T'2)-----(ii)By solving (i) and (ii)T' = 32T
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