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An Intiative by Sri Chaitanya
a
tanϕ2tanϕ1=θ1−θ0θ2−θ0
b
tanϕ2tanϕ1=θ2−θ0θ1−θ0
c
tanϕ1tanϕ2=θ1θ2
d
tanϕ1tanϕ2=θ2θ1
answer is B.
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