A body of density d1 is counterpoised by Mg of weights of density d2 in air of density d. Then the true mass of the body is
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a
M
b
M 1−dd2
c
M1−dd1
d
M(1−d/d2)(1−d/d1)
answer is D.
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Detailed Solution
Let M0 = mass of body in vacuum.Apparent weight of the body in air = Apparent weight of standard weights in air⇒ Actual weight – upthrust due to displaced air = Actual weight – upthrust due to displaced air⇒M0g−M0d1 dg=Mg−Md2 dg⇒M0=M1−dd21−dd1