A body is displaced from position A to position B under the influence of three forces P1, P2 and P3. Speed of the body remains unchanged. If work done by P1 is +180J, work done by P2 is -80 J, then what is the work done by P3?

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+ 40 J

- 60 J

100 J

- 100 J

answer is D.

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Detailed Solution

Change in kinetic energy, ΔK=0By work-energy principle, WP1+WP2+WP3=ΔK⇒180+−80+WP3=0⇒WP3=−100 J

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