Questions
A body is dropped on to the floor from a height h. It makes elastic collision with the floor bouncing back to the same height. The frequency of oscillation of its periodic motion is
detailed solution
Correct option is C
The body of mass m is at rest on top. It undergoes free fall and attains a speed of v1 at the bottom.According to the law of conservation of energy, mgh=12mv12 .On simplifying this we get v1=2gh…………..(1)Using this we find the time taken to go down the inclined plane using equations of motion.v=u+at , Substituting v=2gh , u=0 and a=g ,We get 2gh=u+g t ,Therefore, 2ghg =t .This is time of descent. The total time taken to complete one full oscillation will be two times the time taken to reach the ground.Hence 22ghg =Ti.e. T=22hg and f=12g2hTalk to our academic expert!
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