Q.

A body is dropped from the top of the tower of  height ‘h’ after 1sec it is stopped and released what will be height after 2 sec  g=10m/s2

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An Intiative by Sri Chaitanya

a

h-40

b

h-30

c

h-10

d

h-20

answer is B.

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Detailed Solution

The distance covered in 1sec  S=10m;  S=12gt2The distance covered in next 2sec  S=20mTotal distances travelled down is 10+20=30m The height of stone is  h−30m
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