A body at the end of a spring executes SHM with a period t1, while the corresponding period for another spring is t2. If the period of oscillation with the two spring in series is T, then
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a
T=t1+t2
b
T2=t12+t22
c
1T=1t1+1t2
d
1T2=1t12+1t22
answer is B.
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Detailed Solution
T1=2πmk1,T2=2πmk2,T=2πmkeqkeq=k1k2k1+k2 for series) ,t12=2πmk1t22=2πmk2 and T2=2πm1k1+1k2⇒ T2=t12+t22