A body executes sample harmonic motion under the action of a force F1 with a time period (4/5) sec. If the force is changes to F2 it executes SHM with time period (3/5) sec. if both the forces F1 and F2 act simultaneously in the same direction on the body, its time period (in seconds) is:
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a
12/25
b
24/25
c
35/24
d
25/12
answer is A.
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Detailed Solution
or k=k1+k2or mω2=mω12+mω22or ω2=ω12+ω22∴T=T1T2T12+T22=45×35452+352=1225sec