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Q.

A body executes sample harmonic motion under the action of a force F1  with a time period (4/5) sec. If the force is changes to F2  it executes SHM with time period (3/5) sec. if both the forces   F1 and F2  act simultaneously in the same direction on the body, its time period (in seconds) is:

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a

12/25

b

24/25

c

35/24

d

25/12

answer is A.

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Detailed Solution

or    k=k1+k2or   mω2=mω12+mω22or   ω2=ω12+ω22∴T=T1T2T12+T22=45×35452+352=1225sec
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