Questions
A body executes simple harmonic motion. The potential energy (PE), kinetic energy (KE) and total energy (TE) are measured as a function of displacement x. Which of the following statement is true?
detailed solution
Correct option is C
y=xPE=12mω2y2KE=12mω2a2−y2TE=PE+KE=12mω2a2Since PE is maximum at x = a and KE is maximum at x = 0, therefore TE remains constant throughout the motion.Talk to our academic expert!
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When the displacement is half the amplitude, the ratio of potential energy to the total energy is
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