Questions
A body executes simple harmonic motion the potential energy (PE). The kinetic energy (KE) and total energy (TE) are measured as a function of displacement x. Which of the following statement is true?
detailed solution
Correct option is A
At x=0, KE is maximum and PE is minimum∴KE= K=12mω2(A2-x2) here m = mass of oscillator, w= angular frequency,A= amplitude, x= displacement of oscillatorWhen x=0, K=12mω2A2 = (maximum)And at x=0, PE=12mω2x2 =0 (minimum)So KE is maximum at x=0.Similar Questions
When the displacement is half the amplitude, the ratio of potential energy to the total energy is
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests