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Q.

A body executes simple harmonic motion the potential energy (PE), the kinetic energy (KE) and total energy (TE) are measured as a function of displacement x. Which of the following statement is true?

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a

KE is maximum when x=0

b

TE is zero when x=0

c

KE is maximum when x is maximum

d

PE is maximum when x=0

answer is A.

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Detailed Solution

At x=0, KE is maximum and PE is minimumkinetic energy of simple harmonic oscillator is = K=12mω2(A2-x2) When x=0, K=12mω2(A2) this is maximum energy potential energy of simple harmonic oscillator is = PE==12mω2(x2) When x=0, PE=0 total energy of a simple harmonic oscillator =TE=12mω2(A2)=constant

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A body executes simple harmonic motion the potential energy (PE), the kinetic energy (KE) and total energy (TE) are measured as a function of displacement x. Which of the following statement is true?