A body executing SHM at a displacement 'x' it’s PE is E1,at a displacement ‘y’ its PE is E2. The PE at a displacement (x+y) is
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a
E=E1−E2
b
E=E1+E2
c
E=E1+E2
d
E=E1-E2
answer is B.
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Detailed Solution
PE of a simple harmonic oscillator is PE=12mω2y2, here m= mass, ω= angular velocity, y=displacement PEαy2⇒PE α y, where mω2=constant y=kPE ,here PE=E Given at displacement x, PE=E1⇒ x=KE1----(1) at displacement y,PE=E2⇒y=KE2----(2) at displacement x+y, let PE be E,⇒x+y=KE----(3) substitute eqn 1,2 in 3 ⇒KE1+KE2=KE E=E1+E2