Download the app

Questions  

A body executing SHM at a displacement 'x' it’s PE is E1,at a displacement ‘y’ its PE is E2. The PE at a displacement (x+y) is 

a
E=E1−E2
b
E=E1+E2
c
E=E1+E2
d
E=E1-E2

detailed solution

Correct option is B

PE of a simple harmonic oscillator is PE=12mω2y2, here m= mass, ω= angular velocity, y=displacement PEαy2⇒PE α y, where mω2=constant y=kPE  ,here PE=E      Given at displacement x, PE=E1⇒ x=KE1----(1)                    at displacement y,PE=E2⇒y=KE2----(2)  at displacement  x+y, let PE be E,⇒x+y=KE----(3) substitute eqn 1,2 in 3 ⇒KE1+KE2=KE E=E1+E2

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

When the displacement is half the amplitude, the ratio of potential energy to the total energy is


phone icon
whats app icon