Q.

A body executing SHM has a maximum acceleration equal to 48 m/sec2 and maximum velocity equal to 12 m/sec. The amplitude of SHM is

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a

3 m

b

332 m

c

10249 m

d

649 m

answer is A.

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Detailed Solution

given maximum acceleration amax=48m/s2Maximum velocity  Vmax=12m/samplitude A=? here angular velocity =ωamaxVmax=ω2AωA=4812=4=> ω=4 Vmax=ωAsubstitute maximum velocity, and angular velocity12=4(A)A=3m.
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