Questions
A body executing SHM has a maximum velocity 1 m/sec, maximum acceleration of . It’s amplitude in meters is
detailed solution
Correct option is D
Given velocity maximum is vmax=1m/s=ωA, here w=angular velocity,A=amplitude acceleration maximum amax=4m/s2=ω2A divide above two equations ω=amax/vmax=4 we know that, vmax=A×ω ⇒A=vmaxω, here A=amplitude ⇒A=14=0.25 mTalk to our academic expert!
Similar Questions
A horizontal platform with an object placed on it is executing S.H.M. in the vertical direction. The amplitude of oscillation is . What must be the least period of these oscillations, so that the object is not detached from the platform
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