A body executing SHM has a maximum velocity 1 m/sec, maximum acceleration of 4 m/sec2. It’s amplitude in meters is

Given vmax=1m/svmax=1m/s2=ωA---(1) . here ω is angular velocity, A is amplitude amax=4m/s2=-ω2A---(2) squaring equation (1) ÷equation(2)                  14=ω2A2ω2A              ⇒14=A=0.25 m