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Q.

A body is executing SHM under the action of a force whose maximum magnitude is 50 N. The magnitude of force acting on the particle at the time when its energy is half kinetic and half-potential is (Assume potential energy to be zero at mean position).

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a

12.52 N

b

12.5 N

c

25 N

d

252 N

answer is D.

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Detailed Solution

Fmax = mω2A = 50 NGiven 12kx2 = 12[12kA2]   ⇒ x = A2F = mω2x = mω2A2 = 502 = 252 N
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