First slide

Simple hormonic motion

Question

A body is executing SHM under the action of a force whose maximum magnitude is 50 N. The magnitude of force acting on the particle at the time when its energy is half kinetic and half potential is

Moderate

A

25 N
B

25√2N
C

$\frac{25}{\sqrt{2}} N$
D

12.5 N

Solution

$f_{\max} = {mAω}^{2} = 50 N; PE = KE at x = \frac{A}{\sqrt{2}}$
$f = {mω}^{2} x$

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