First slide

Simple harmonic motion

Question

A body is executing S.H.M. When its displacement from the mean position is 4 cm and 5 cm, the corresponding velocity of the body is 10 cm/sec and 8 cm/sec. Then the time period of the body is

Moderate

A

$2 π \sec$
B

$π / 2 \sec$
C

$π \sec$
D

$3 π / 2 \sec$

Solution

$v = ω \sqrt{a^{2} - y^{2}}$ $\Rightarrow 10 = ω \sqrt{a^{2} - {(4)}^{2}}$ and $8 = ω \sqrt{a^{2} - {(5)}^{2}}$
On solving $A = 41 and ω = 2 r a d / s$ $\Rightarrow ω = \frac{2 π}{T} = 2$ $\Rightarrow T = πsec$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App