A body executing simple harmonic motion has a maximum acceleration equal to 24metres/sec2 and maximum velocity equal to 16 metres/sec . The amplitude of the simple harmonic motion is
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a
323metres
b
332metres
c
10249metres
d
649metres
answer is A.
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Detailed Solution
Maximum velocity =aω = 16Maximum acceleration =ω2a=24⇒a=(aω)2ω2a=16×1624=323m