First slide
Simple hormonic motion
Question

A body is executing a simple harmonic motion such that its potential energy is U1 at x and U2 at y. When the displacement is x+y , the potential energy will be

Moderate
Solution

At displacement x, U1 = 122x2

 x= 2U12

Similarly, y = 2U22

When displacement is (x+y), potential energy is

U = 122(x+y)2 = 122(x2+y2+2xy)

     = 122x2+122y2+2xy

      = U1+U2+22U12.2U22

     = U1+U2+U1U22

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