A body falling from a high Minaret travels 40 m in the last 2 seconds of its fall to ground. Height of Minaret in metre is (Take, g = 10 ms-2)

Let height of Minaret be H and body take time T to fall from top to bottom.                                H = 12gT2                                                …(i)In last 2 s, body travels distance of 40 m, so in (T - 2) second, distance travelled = (H - 40) m⇒               (H-40)=12g(T-2)2                                            …(ii)By solving Eqs. (i) and (ii), we get                          T = 3 s and H = 45 m