A body falls from a height  h=300m, the ratio of distances travelled in each  2s, during  t=0 to t=6s in the journey is:…….

For a freely body s=12gt2 For first  2s: s1=12g(2)2=12g(4)………..(i) For the next 2s: s2=12g(4)2−12g(2)2 =12g[16−4] =12g[12]……...(ii) For last 2s: s3=12g(6)2−44 =12g[36−16]=12g(20)……...(iii)The ratio of all these distance is s1:s2:s3=12g(4):12g(12):12g(20)              =4:12:20              =1:3:5