First slide

Position Path Length (Distance) And Displacement

Question

A body falls from rest freely under gravity with an acceleration of 9.8 m/s². Neglecting air resistance, the distance travelled by the body during the third second of its motion will be

Easy

A

14.7 m
B

24.5 m
C

19.6 m
D

29.4 m

Solution

$S_{n} = u + \frac{a}{2} (2 n - 1)$
$\Rightarrow S_{3^{rd}} = 0 + \frac{9 .8}{2} (2 \times 3 - 1) = 24 .5 m$

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