A body falls from rest freely under gravity with an acceleration of 9.8 m/s2. Neglecting air resistance, the distance travelled by the body during the third second of its motion will be

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14.7 m

24.5 m

19.6 m

29.4 m

answer is B.

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Detailed Solution

Sn=u+a22n−1⇒S3rd=0+9.822×3−1=24.5m

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