Q.
A body falls from rest freely under gravity with an acceleration of 9.8 m/s2. Neglecting air resistance, the distance travelled by the body during the third second of its motion will be
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a
14.7 m
b
24.5 m
c
19.6 m
d
29.4 m
answer is B.
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Detailed Solution
Sn=u+a22n−1⇒S3rd=0+9.822×3−1=24.5m
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