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Q.

A body is floating in a liquid filled in a beaker such that 60% of its volume is submerged in the liquid. Now the beaker starts moving downward with an acceleration g/2. What percent of its volume is submerged in the liquid in this case?

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a

40%

b

60%

c

20%

d

30%

answer is B.

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Detailed Solution

If ρl and ρb be the densities of the liquid and the body respectively, then initially, ρbv0g=ρlvg⇒vv0=ρbρlFor accelerated beaker, ρbv0g-ρbv0g/2=v'ρlg-g2⇒v'v0=ρbρlHence, acceleration of beaker has no effect on volume submerged.

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A body is floating in a liquid filled in a beaker such that 60% of its volume is submerged in the liquid. Now the beaker starts moving downward with an acceleration g/2. What percent of its volume is submerged in the liquid in this case?