A body has an initial velocity of 3 ms-1 and has an acceleration of 1 ms-1 normal to the direction of the initial velocity. Then its velocity 4 s after the start is

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7 ms-1 along the direction of initial velocity

7 ms-1 along the normal to the direction of initial velocity.

7ms-1 midway between the two directions

5 ms-1 at an angle tan-1(4/3) with the direction of initial velocity.

answer is D.

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Detailed Solution

Let yx=3ms−1,ax=0 yx=yx+aytt=0+1×4=4ms−1 Angle made by the resultant velocity w.r.t. direction of initial velocity, i.e., x-axis, is β=tan−1⁡Vyvx=tan−1⁡43

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