Q.
A body having kinetic energy K moving on a rough horizontal surface is stopped in a distance x. The force of friction exerted on the body is
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a
K/x
b
K/x
c
K/x
d
Kx
answer is B.
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Detailed Solution
Let f be the force of friction and m, the mass of the body.∴ Retardation a=f/mLet v be the initial velocity of the body, thenv2=2ax or 12mv2=maxor K = fx (∵ma=f)∴ f=K/x.
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