Q.
A body of 2 kg has an initial speed 5 ms-1. A force acts on it for some time in the direction of motion. The force time graph is shown in figure. The final speed of the body is
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a
9.25 ms-1
b
5 ms-1
c
14.3 ms-1
d
4.25 ms-1
answer is C.
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Detailed Solution
Impulse = Change in momentum = m(v2-v1)----(i)Again impulse = Area between the graph and time axis= 12×2×4+2×4+12(4+2.5)×0.5+2×2.5= 4+8+1.625+5 = 18.625----------(ii)From (i) and (ii), m(v2-v1) = 18.625⇒ v2 = 18.625m+v1 = 18.6252+5 = 14.3 m/s