Questions
A body of 2 kg has an initial speed 5 . A force acts on it for some time in the direction of motion. The force time graph is shown in figure. The final speed of the body is
detailed solution
Correct option is C
Impulse = Change in momentum = m(v2-v1)----(i)Again impulse = Area between the graph and time axis= 12×2×4+2×4+12(4+2.5)×0.5+2×2.5= 4+8+1.625+5 = 18.625----------(ii)From (i) and (ii), m(v2-v1) = 18.625⇒ v2 = 18.625m+v1 = 18.6252+5 = 14.3 m/sTalk to our academic expert!
Similar Questions
Figures I, II, III and IV depict variation of force with time. Select the figure(s) that depicts minimum impulse delivered.
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
