First slide

Conduction

Question

A body of length 1 m having cross sectional area 0.75 $m^{2}$ has heat flow through it at the rate of 6000 Joule/sec. Then find the temperature difference across it if K = 200 ${Jm}^{- 1} K^{- 1}$

Moderate

A

$20^{0} C$
B

$40^{0} C$
C

$80^{0} C$
D

$100^{0} C$

Solution

$\frac{Q}{t} = \frac{KA ∆ θ}{l}$
$\Rightarrow 6000 = \frac{200 \times 0.75 \times ∆ θ}{1}$
$∆ θ = \frac{6000 \times 1}{200 \times 0.75} = 40^{0} C$

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