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A body of length 1 m having cross sectional area 0.75 $m^{2}$ has heat flow through it at the rate of 6000 Joule/sec. Then find the temperature difference across it if K = 200 ${Jm}^{- 1} K^{- 1}$

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Correct option is B

Qt = KA∆θl⇒ 6000 = 200×0.75×∆θ1∆θ = 6000×1200 × 0.75 = 400C

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A body of length 1 m having cross sectional area 0.75 m2 has heat flow through it at the rate of 6000 Joule/sec. Then find the temperature difference across it if K = 200 Jm-1K-1

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Ready to Test Your Skills?

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A body of length 1 m having cross sectional area 0.75 $m^{2}$ has heat flow through it at the rate of 6000 Joule/sec. Then find the temperature difference across it if K = 200 ${Jm}^{- 1} K^{- 1}$