First slide

Friction on inclined plane of angle more than angle of repose

Question

A body of mass 500 g is taken up an inlclined plane of length 10 m and height 5 m, and then released to slide down to the bottom. The coefficient of friction between the body and the plane is 0.1. What is the amount of work done in the round trip ?

Moderate

A

$5 J$
B

$15 J$
C

$5 \sqrt{3} J$
D

$\frac{5}{\sqrt{3}} J$

Solution

$h e r e w o r k d o n e i s o n l y d u e t o f r i c t i o n i n b o t h t h e w a y s a s i t i s a n o n \cos e r v a t i v e f o r c e w = μ m g \cos θ l x 2 h e r e \sin θ = \frac{h}{l} = \frac{5}{10} = 0.5 θ = 30^{0} w = 0.1 x 0.5 x 10 x 10 x \frac{\sqrt{3}}{2} x 2 = 5 \sqrt{3}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App