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Q.

A body of mass 5 gm is executing S.H.M. about a point with amplitude 10 cm. Its maximum velocity is 100 cm/sec. Its velocity will be 50 cm/sec at a distance

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a

5

b

52

c

53

d

102

answer is C.

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Detailed Solution

It is given vmax=100 cm/sec , a = 10 cm.⇒vmax=aω  ⇒ω=10010=10 rad/sec  Hence v=ωa2−y2  ⇒50=10(10)2−y2 ⇒y=53 cm
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