Questions
A body of mass 5 gm is executing S.H.M. about a point with amplitude 10 cm. Its maximum velocity is 100 cm/sec. Its velocity will be 50 cm/sec at a distance
detailed solution
Correct option is C
It is given vmax=100 cm/sec , a = 10 cm.⇒vmax=aω ⇒ω=10010=10 rad/sec Hence v=ωa2−y2 ⇒50=10(10)2−y2 ⇒y=53 cmTalk to our academic expert!
Similar Questions
A horizontal platform with an object placed on it is executing S.H.M. in the vertical direction. The amplitude of oscillation is . What must be the least period of these oscillations, so that the object is not detached from the platform
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