Questions
A body of mass 100 gm is executing simple harmonic motion. Its displacement x (in cm) at time t (in second) is given by . Then maximum restoring force acting on the body is
detailed solution
Correct option is C
m = 0.1 kg, Amplitude A = 0.1 m and ω=50 rad/s∴ Maximum restoring force =mω2A=0.1×(50)2×0.1 N=25 NTalk to our academic expert!
Similar Questions
The identical springs of constant ‘K’ are connected in series and parallel as shown in figure A mass M is suspended from them. The ratio of their frequencies of vertical oscillations will be
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
