First slide

Simple hormonic motion

Question

A body of mass 100 gm is executing simple harmonic motion. Its displacement x (in cm) at time t (in second) is given by $x = 10 \cos (50 t - π / 3)$ . Then maximum restoring force acting on the body is

Moderate

A

7.5 N
B

75 N
C

25 N
D

50 N

Solution

m = 0.1 kg, Amplitude A = 0.1 m and $ω = 50 r a d / s$
$∴$ Maximum restoring force $= m ω^{2} A = 0.1 \times (50)^{2} \times 0.1 N = 25 N$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App