Questions

A body of mass 40 grams executes simple harmonic motion of amplitude 2 cm. If the time period is 0.20 seconds. What would be the total mechanical energy of system?

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14.8×10−3J

7.9×10−3J

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detailed solution

Correct option is B

Total mechanical energy of the system (given m=40 g)E=12mω2a2=12×40×10-3×2πT22×10-22 =12×40×10-32×3.140.22×2×10-22 =7.9×10−3J

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