First slide
Second law
Question

A body of mass 10 kg is acted upon by two perpendicular forces 6 N and 8 N. The resultant acceleration of the body is :
(i) 1ms-2 at an angle of tan143 w.r.t. 6 N force
(ii) 0.2ms-2 at an angle of tan143 w.r.t. 6 N force
(iii) 1ms-2 at an angle of tan134 w.r.t. 8N force
(iv) 0.2ms-2 at an angle of tan134 w.r.t. 8N force

Easy
Solution


Resultant force 82+62=10 NAcceleration=10N10 kg=1m/s2tanθ1=86=43tanθ2=68=34

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