A body of mass 10 kg is acted upon by two perpendicular forces 6 N and 8 N. The resultant acceleration of the body is :(i) 1ms-2 at an angle of tan−143 w.r.t. 6 N force(ii) 0.2ms-2 at an angle of tan−143 w.r.t. 6 N force(iii) 1ms-2 at an angle of tan−134 w.r.t. 8N force(iv) 0.2ms-2 at an angle of tan−134 w.r.t. 8N force
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a
(i, iii)
b
(i, iv)
c
(ii, iii)
d
(ii, iv)
answer is A.
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Detailed Solution
Resultant force 82+62=10 NAcceleration=10N10 kg=1m/s2tanθ1=86=43tanθ2=68=34
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A body of mass 10 kg is acted upon by two perpendicular forces 6 N and 8 N. The resultant acceleration of the body is :(i) 1ms-2 at an angle of tan−143 w.r.t. 6 N force(ii) 0.2ms-2 at an angle of tan−143 w.r.t. 6 N force(iii) 1ms-2 at an angle of tan−134 w.r.t. 8N force(iv) 0.2ms-2 at an angle of tan−134 w.r.t. 8N force