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A body of mass 10 kg is acted upon by two perpendicular forces 6 N and 8 N. The resultant acceleration of the body is :
(i) 1ms-2 at an angle of tan143 w.r.t. 6 N force
(ii) 0.2ms-2 at an angle of tan143 w.r.t. 6 N force
(iii) 1ms-2 at an angle of tan134 w.r.t. 8N force
(iv) 0.2ms-2 at an angle of tan134 w.r.t. 8N force

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a
(i, iii)
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(ii, iii)
d
(ii, iv)

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detailed solution

Correct option is A

Resultant force 82+62=10 NAcceleration=10N10 kg=1m/s2tan⁡θ1=86=43tan⁡θ2=68=34


Similar Questions

Statement I : The familiar equation mg = R for a body on a table is true only if the body is in equilibrium.

Statement II : The equality of mg and R has no connection with the third law.


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