A body of mass 10 kg is acted upon by two perpendicular forces 6 N and 8 N. The resultant acceleration of the body is :(i) 1ms-2 at an angle of tan−1⁡43 w.r.t. 6 N force(ii) 0.2ms-2 at an angle of tan−1⁡43 w.r.t. 6 N force(iii) 1ms-2 at an angle of tan−1⁡34 w.r.t. 8N force(iv) 0.2ms-2 at an angle of tan−1⁡34 w.r.t. 8N force

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(i, iii)

(i, iv)

(ii, iii)

(ii, iv)

answer is A.

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Detailed Solution

Resultant force 82+62=10 NAcceleration=10N10 kg=1m/s2tan⁡θ1=86=43tan⁡θ2=68=34

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