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Q.

The body of mass 2kg is attached to a wire 1m long its breaking strength is 2×107Nm−2  It can be rotated in a horizontal circle with maximum angular velocity 10rads−1 , Then the area of cross –section of the wire is

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a

5×10−7m2

b

100×10−7m2

c

50×10−7m2

d

25×10−1m2

answer is B.

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Detailed Solution

FA=2×107⇒mrω2A=2×107 A=mrω22×107=2×1×1022×107=10-5=100×10−7m2
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