First slide

Work done by Diff type of forces

Question

A body of mass 2 kg is being dragged with uniform velocity of 2 m/s on a rough horizontal plane. The coefficient of friction between the body and the surface is 0.20. The amount of heat generated in 5 sec is $(J = 4 .2 joule / cal and g = 9 .8 m / s^{2})$

Moderate

A

9.33 cal
B

10.21 cal
C

12.67 cal
D

13.34 cal

Solution

$\begin{aligned} Workdone = Force \times Displacement = μmg \times (u \times t) W = (0 .2) \times 2 \times 9 .8 \times 2 \times 5 joule \end{aligned}$
Heat generated $Q = \frac{W}{J} = \frac{0 .2 \times 2 \times 9 .8 \times 2 \times 5}{4 .2} = 9 .33 cal$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App