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Q.

A body of mass 2 kg collides with a wall with speed 100 m/s and rebounds with same speed. If the time of contact was 1/50 second, the force exerted on the wall is

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a

8 N

b

2×104 N

c

4 N

d

104 N

answer is B.

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F=dpdt=mdvdt=m×2v1​/​50=2×2×1001​/​50=2×104N
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