A body of mass 1kg executing S.H.M., its displacement y cm at t seconds is given  by  $y=6\sin \pi \left(\frac{100}{\pi }t+\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$4$}\right.\right)$. Its maximum kinetic energy is 

detailed solution

Correct option is B

For a body executing simple harmonic motion the maximum kinetic energy will  be  at its mean position. We know that,Mechanical energy = Potential Energy + Kinetic energyAt mean position potential energy is 0. Hence the mechanical energy will be  equal  to maximum kinetic energy.Mechanical energy = 12mω2A2  Where m=1kg, ω=100   rad/s , A=0.06mSubstituting this in the relation for maximum kinetic energy i.e. mechanical energy,  we getME =  121×1002×0.062Hence ME =  1236=18J.