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Q.

A body of mass 1kg executing S.H.M., its displacement y cm at t seconds is given  by  y=6sinπ100πt+14. Its maximum kinetic energy is

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a

6J

b

18J

c

24J

d

36J

answer is B.

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Detailed Solution

For a body executing simple harmonic motion the maximum kinetic energy will  be  at its mean position. We know that,Mechanical energy = Potential Energy + Kinetic energyAt mean position potential energy is 0. Hence the mechanical energy will be  equal  to maximum kinetic energy.Mechanical energy = 12mω2A2  Where m=1kg, ω=100   rad/s , A=0.06mSubstituting this in the relation for maximum kinetic energy i.e. mechanical energy,  we getME =  121×1002×0.062Hence ME =  1236=18J.
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