Simple hormonic motion

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Question

A body of mass 1 kg is executing SHM. Its displacement y (cm) at t seconds is given by $y = 6 \sin (100 t + \frac{π}{4})$ . Its maximum kinetic energy is

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Solution

${KE}_{\max} = \frac{1}{2} {mω}^{2} A^{2} = \frac{1}{2} \times 1 \times 100^{2} \times {(\frac{6}{100})}^{2} = 18 J$

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