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A body of mass $1 kg$ is executing simple harmonic motion. Its displacement $y (cm)$ at t seconds is given by $y = 6 \sin (100 t + π / 4)$ . Its maximum kinetic energy is

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Correct option is B

So a=6cm, ω=100rad/secKmax=12mω2a2=12×1×(100)2×(6×10−2)2=18 J

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A body of mass 1 kg is executing simple harmonic motion. Its displacement y(cm) at t seconds is given by y=6sin(100t+π​/​4) . Its maximum kinetic energy is

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A body of mass $1 kg$ is executing simple harmonic motion. Its displacement $y (cm)$ at t seconds is given by $y = 6 \sin (100 t + π / 4)$ . Its maximum kinetic energy is