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Q.

A body of mass 1 kg is executing simple harmonic motion. Its displacement y(cm)  at t seconds is given by y=6sin(100t+π​/​4) . Its maximum kinetic energy is

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a

6 J

b

18 J

c

24 J

d

36 J

answer is B.

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Detailed Solution

So  a=6cm, ω=100rad/secKmax=12mω2a2=12×1×(100)2×(6×10−2)2=18 J
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