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Q.

A body of mass 5 kg explodes into 3 fragments having masses in the ratio of 2:2:1. The fragments with equal masses fly in merely in perpendicular directions  with speed 15ms−1 . What will be the velocity of lighter one?

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a

15ms−1

b

152ms−1

c

30ms−1

d

302ms−1

answer is D.

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Detailed Solution

Here 1×v=[(2×15)2+(2×15)2]12 ⇒ v=(30)2+(30)2=302ms−1
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