First slide
Law of conservation of momentum and it's applications
Question

A body of mass 5 kg explodes at rest into three fragments with masses in the ratio 1 : 1 : 3. The fragments with equal masses fly in mutually perpendicular directions with speeds of 21 m/s. The velocity of the heaviest fragment will be

Moderate
Solution

Px=m×vx=1×21=21kgm/s

Py=m×vy=1×21=21kgm/s

 Resultant = Px2+Py2=212 kg m/s
The momentum of heavier fragment should be numerically equal to resultant of Px and Py.
 3×v=Px2+Py2=212   v=72 = 9.89 m/s

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