First slide

Fluid statics

Question

A body of mass 2 kg is floating in water with half of its volume submerged. What would be the force required to wholly submerge it into water ?

Moderate

A

2 N
B

9.8 N
C

19.6 N
D

4.9 N

Solution

$Upthrust = \frac{V}{2} \times 1000 \times g newton In equilibrium position, M g = upthrust ∴ 2 g = \frac{V}{2} \times 1000 \times g or V = \frac{4}{1000} m^{3} So, the force required to wholly submerge the body into water = \frac{V}{2} \times d \times g = (\frac{4}{1000 \times 2}) \times 1000 \times 9 \cdot 8 = 19 . 6 newton$

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