Questions
A body of mass 2 kg has an initial velocity of 3 meters per second along OE and it is subjected to a force of 4 N in a direction perpendicular to OE. The distance of the body
from O after 4 seconds will be
detailed solution
Correct option is B
Displacement of body in 4 sec along OEsx=vxt=3×4=12mForce along OF (perpendicular to OE)=4 N∴ ay=Fm=42=2m/s2Displacement of body in 4 sec along OF⇒ sy=uyt+12ayt2=12×2×(4)2=16m As uy=0∴ Net displacement s=sx2+sy2=(12)2+(16)2=20mTalk to our academic expert!
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A block of mass kg rests on a horizontal frictionless xy-plane. What would be the acceleration of the block if it is subjected to two forces as shown in figure?
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