A body of mass $$1$$ kg initially at rest, explodes and breaks into three fragments of masses in the ratio $$1$$ : $$1$$: $$3$$. The two pieces of equal mass fly off perpendicular to each other with a speed of $$15$$ $$ms-1$$ each. What is the velocity of the heavier fragment?

Question

Infinity Learn · Accepted Answer

Conservation of momentum during explosion yields⇒ P→$$1+P$$→$$2+P$$→$$3=0$$⇒$$P3$$→$$=P$$→$$1+P$$→$$2$$⇒ $$m3$$ $$v3$$→$$=m1v$$→$$1+m2v$$→$$2$$ since v→$$1$$⊥v→$$2$$⇒ $$v3$$→$$=m1m32v12+m2m32v22$$⇒ $$132(15)2+132(15)2$$ ∴$$m1$$:$$m2$$:$$m3=1$$:$$1$$:$$3$$⇒ $$v3=52ms$$−$$1$$

A body of mass 1 kg initially at rest, explodes and breaks into three fragments of masses in the ratio 1 : 1: 3. The two pieces of equal mass fly off perpendicular to each other with a speed of 15 ms^-1 each. What is the velocity of the heavier fragment?

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A body of mass 1 kg initially at rest, explodes and breaks into three fragments of masses in the ratio 1 : 1: 3. The two pieces of equal mass fly off perpendicular to each other with a speed of 15 ms-1 each. What is the velocity of the heavier fragment?

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A body of mass 1 kg initially at rest, explodes and breaks into three fragments of masses in the ratio 1 : 1: 3. The two pieces of equal mass fly off perpendicular to each other with a speed of 15 ms^-1 each. What is the velocity of the heavier fragment?