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A body of mass 8 kg lies on a rough horizontal table. It is observed that a certain horizontal force gives the body an acceleration of 4m/s2 . When this force is doubled, the acceleration of the body is 16m/s2. The coefficient of friction is

a
0.2
b
0.3
c
0.4
d
0.8

detailed solution

Correct option is D

F−f=8×4=322F−f=128f=64N⇒μmg=64⇒μ=0.8

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